在SMDK2440的BSP包里經(jīng)??匆娺@兩句語句:volatile IOPreg *s2440IOP = (IOPreg *)IOP_BASE;
volatile INTreg *s2440INT = (INTreg *)INT_BASE;
本文引用地址:
http://m.butianyuan.cn/article/201611/320093.htm這兩條語句簡單的理解就是把s2440IOP和IOP_BASE等價,把s2440INT和INT_BASE等價。
IOP_BASE和INT_BASE在s244.h頭文件中
#define IOP_BASE 0xB1600000 // 0x56000000
typedef struct {
unsigned int rGPACON;// 00
unsigned int rGPADAT;
unsigned int rPAD1[2];
unsigned int rGPBCON;// 10
unsigned int rGPBDAT;
unsigned int rGPBUP;
unsigned int rPAD2;
unsigned int rGPCCON;// 20
unsigned int rGPCDAT;
unsigned int rGPCUP;
unsigned int rPAD3;
unsigned int rGPDCON;// 30
unsigned int rGPDDAT;
unsigned int rGPDUP;
unsigned int rPAD4;
unsigned int rGPECON;// 40
unsigned int rGPEDAT;
unsigned int rGPEUP;
unsigned int rPAD5;
unsigned int rGPFCON;// 50
unsigned int rGPFDAT;
unsigned int rGPFUP;
unsigned int rPAD6;
unsigned int rGPGCON;// 60
unsigned int rGPGDAT;
unsigned int rGPGUP;
unsigned int rPAD7;
unsigned int rGPHCON;// 70
unsigned int rGPHDAT;
unsigned int rGPHUP;
unsigned int rPAD8;
unsigned int rMISCCR;// 80
unsigned int rDCKCON;
unsigned int rEXTINT0;
unsigned int rEXTINT1;
unsigned int rEXTINT2;// 90
unsigned int rEINTFLT0;
unsigned int rEINTFLT1;
unsigned int rEINTFLT2;
unsigned int rEINTFLT3;// A0
unsigned int rEINTMASK;
unsigned int rEINTPEND;
unsigned int rGSTATUS0;// AC
unsigned int rGSTATUS1;// B0
unsigned int rGSTATUS2;// B4 ;;; SHL
unsigned int rGSTATUS3;// B8
unsigned int rGSTATUS4;// BC
unsigned int rFLTOUT;// C0
unsigned int rDSC0;
unsigned int rDSC1;
unsigned int rMSLCON;
unsigned int rGPJCON;// D0
unsigned int rGPJDAT;
unsigned int rGPJUP;
unsigned int rPAD9;
}IOPreg;
#define INT_BASE 0xB0A00000 // 0x4A000000
typedef struct {
unsigned int rSRCPND;
unsigned int rINTMOD;
unsigned int rINTMSK;
unsigned int rPRIORITY;
unsigned int rINTPND;
unsigned int rINTOFFSET;
unsigned int rSUBSRCPND;
unsigned int rINTSUBMSK;
}INTreg ;
可見IOPreg和INTreg是兩個結構體,而INT_BASE和IOP_BASE是連個虛擬地址。因此上面的兩條語句就是把兩個虛擬地址強化成結構體的首地址,因此可以訪問結構體對應的寄存器了。
評論