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ARM Linux 進程調(diào)度(2.4.x)

作者: 時間:2011-02-25 來源:網(wǎng)絡(luò) 收藏
ARM Linux 進程調(diào)度(2.4.x) FireAngel(原作)

小弟最近研究了一段時間的ARM Linux,想把進程管理方面的感受跟大家交流下,不對的地方多多指點

----------------------------------------------

Process Creation and Termination
Process Scheduling and Dispatching
Process Switching
Porcess Synchronization and support for interprocess communication
Management of process control block

-------from Operating system:internals and design principles>


進程調(diào)度


Linux2.4.x是一個基于非搶占式的多任務(wù)的分時操作系統(tǒng),雖然在用戶進程的調(diào)度上采用搶占式策略,但是而在內(nèi)核還是采用了輪轉(zhuǎn)的方法,如果有個內(nèi)核態(tài)的線程惡性占有CPU不釋放,那系統(tǒng)無法從中解脫出來,所以實時性并不是很強。這種情況有望在Linux 2.6版本中得到改善,在2.6版本中采用了搶占式的調(diào)度策略。


內(nèi)核中根據(jù)任務(wù)的實時程度提供了三種調(diào)度策略:


1. SCHED_OTHER為非實時任務(wù),采用常規(guī)的分時調(diào)度策略;


2. SCHED_FIFO為短小的實時任務(wù),采用先進先出式調(diào)度,除非有更高優(yōu)先級進程申請運行,否則該進程將保持運行至退出才讓出CPU;


3. SCHED_RR任務(wù)較長的實時任務(wù),由于任務(wù)較長,不能采用FIFO的策略,而是采用輪轉(zhuǎn)式調(diào)度,該進程被調(diào)度下來后將被置于運行隊列的末尾,以保證其他實時進程有機會運行。


需要說明的是,SCHED_FIFO和SCHED_RR兩種調(diào)度策略之間沒有優(yōu)先級上的區(qū)別,主要的區(qū)別是任務(wù)的大小上。另外,task_struct結(jié)構(gòu)中的policy中還包含了一個SCHED_YIELD位,置位時表示該進程主動放棄CPU。


在上述三種調(diào)度策略的基礎(chǔ)上,進程依照優(yōu)先級的高低被分別調(diào)系統(tǒng)。優(yōu)先級是一些簡單的整數(shù),它代表了為決定應(yīng)該允許哪一個進程使用CPU的資源時判斷方便而賦予進程的權(quán)值——優(yōu)先級越高,它得到CPU時間的機會也就越大。


在Linux中,非實時進程有兩種優(yōu)先級,一種是靜態(tài)優(yōu)先級,另一種是動態(tài)優(yōu)先級。實時進程又增加了第三種優(yōu)先級,實時優(yōu)先級。


1. 靜態(tài)優(yōu)先級(priority)——被稱為“靜態(tài)”是因為它不隨時間而改變,只能由用戶進行修改。它指明了在被迫和其它進程競爭CPU之前該進程所應(yīng)該被允許的時間片的最大值(20)。


2. 動態(tài)優(yōu)先級(counter)——counter 即系統(tǒng)為每個進程運行而分配的時間片,Linux兼用它來表示進程的動態(tài)優(yōu)先級。只要進程擁有CPU,它就隨著時間不斷減??;當(dāng)它為0時,標記進程重新調(diào)度。它指明了在當(dāng)前時間片中所剩余的時間量(最初為20)。


3. 實時優(yōu)先級(rt_priority)——值為1000。Linux把實時優(yōu)先級與counter值相加作為實時進程的優(yōu)先權(quán)值。較高權(quán)值的進程總是優(yōu)先于較低權(quán)值的進程,如果一個進程不是實時進程,其優(yōu)先權(quán)就遠小于1000,所以實時進程總是優(yōu)先。


在每個tick到來的時候(也就是時鐘中斷發(fā)生),系統(tǒng)減小當(dāng)前占有CPU的進程的counter,如果counter減小到0,則將need_resched置1,中斷返回過程中進行調(diào)度。update_process_times()為時鐘中斷處理程序調(diào)用的一個子函數(shù):


void update_process_times(int user_tick)
{
struct task_struct *p = current;
int cpu = smp_processor_id(), system = user_tick ^ 1;

update_one_process(p, user_tick, system, cpu);
if (p->pid) {
if (--p->counter = 0) {
p->counter = 0;
p->need_resched = 1;
}
if (p->nice > 0)
kstat.per_cpu_nice[cpu] = user_tick;
else
kstat.per_cpu_user[cpu] = user_tick;
kstat.per_cpu_system[cpu] = system;
} else if (local_bh_count(cpu) || local_irq_count(cpu) > 1)
kstat.per_cpu_system[cpu] = system;
}

Linux中進程的調(diào)度使在schedule()函數(shù)中實現(xiàn)的,該函數(shù)在下面的ARM匯編片斷中被調(diào)用到:

/*
* This is the fast syscall return path. We do as little as
* possible here, and this includes saving r0 back into the SVC
* stack.
*/
ret_fast_syscall:
ldr r1, [tsk, #TSK_NEED_RESCHED]
ldr r2, [tsk, #TSK_SIGPENDING]
teq r1, #0 need_resched || sigpending
teqeq r2, #0
bne slow
fast_restore_user_regs

/*
* Ok, we need to do extra processing, enter the slow path.
*/
slow: str r0, [sp, #S_R0 S_OFF]! returned r0
b 1f

/*
* "slow" syscall return path. "why" tells us if this was a real syscall.
*/
reschedule:
bl SYMBOL_NAME(schedule)
ENTRY(ret_to_user)
ret_slow_syscall:
ldr r1, [tsk, #TSK_NEED_RESCHED]
ldr r2, [tsk, #TSK_SIGPENDING]
1: teq r1, #0 need_resched => schedule()
bne reschedule 如果需要重新調(diào)度則調(diào)用schedule
teq r2, #0 sigpending => do_signal()
blne __do_signal
restore_user_regs



而這段代碼在中斷返回或者系統(tǒng)調(diào)用返回中反復(fù)被調(diào)用到。

1. 進程狀態(tài)轉(zhuǎn)換時: 如進程終止,睡眠等,當(dāng)進程要調(diào)用sleep()或exit()等函數(shù)使進程狀態(tài)發(fā)生改變時,這些函數(shù)會主動調(diào)用schedule()轉(zhuǎn)入進程調(diào)度。

2. 可運行隊列中增加新的進程時;

ENTRY(ret_from_fork)
bl SYMBOL_NAME(schedule_tail)
get_current_task tsk
ldr ip, [tsk, #TSK_PTRACE] check for syscall tracing
mov why, #1
tst ip, #PT_TRACESYS are we tracing syscalls?
beq ret_slow_syscall
mov r1, sp
mov r0, #1 trace exit [IP = 1]
bl SYMBOL_NAME(syscall_trace)
b ret_slow_syscall 跳轉(zhuǎn)到上面的代碼片斷



3. 在時鐘中斷到來后:Linux初始化時,設(shè)定系統(tǒng)定時器的周期為10毫秒。當(dāng)時鐘中斷發(fā)生時,時鐘中斷服務(wù)程序timer_interrupt立即調(diào)用時鐘處理函數(shù)do_timer( ),在do_timer()會將當(dāng)前進程的counter減1,如果counter為0則置need_resched標志,在從時鐘中斷返回的過程中會調(diào)用schedule.

4. 進程從系統(tǒng)調(diào)用返回到用戶態(tài)時;判斷need_resched標志是否置位,若是則轉(zhuǎn)入執(zhí)行schedule()。系統(tǒng)調(diào)用實際上就是通過軟中斷實現(xiàn)的,下面是ARM平臺下軟中斷處理代碼。

.align 5
ENTRY(vector_swi)
save_user_regs
zero_fp
get_scno

enable_irqs ip

str r4, [sp, #-S_OFF]! push fifth arg

get_current_task tsk
ldr ip, [tsk, #TSK_PTRACE] check for syscall tracing
bic scno, scno, #0xff000000 mask off SWI op-code
eor scno, scno, #OS_NUMBER 20 check OS number
adr tbl, sys_call_table load syscall table pointer
tst ip, #PT_TRACESYS are we tracing syscalls?
bne __sys_trace

adrsvc al, lr, ret_fast_syscall 裝載返回地址,用于在跳轉(zhuǎn)調(diào)用后返回到
上面的代碼片斷中的ret_fast_syscall
cmp scno, #NR_syscalls check upper syscall limit
ldrcc pc, [tbl, scno, lsl #2] call sys_* routine

add r1, sp, #S_OFF
2: mov why, #0 no longer a real syscall
cmp scno, #ARMSWI_OFFSET
eor r0, scno, #OS_NUMBER 20 put OS number back
bcs SYMBOL_NAME(arm_syscall)
b SYMBOL_NAME(sys_ni_syscall) not private func



5. 內(nèi)核處理完中斷后,進程返回到用戶態(tài)。

6. 進程主動調(diào)用schedule()請求進行進程調(diào)度。

----------------------------------------------

schedule()函數(shù)分析:


/*
* 'schedule()' is the scheduler function. It's a very simple and nice
* scheduler: it's not perfect, but certainly works for most things.
*
* The goto is "interesting".
*
* NOTE!! Task 0 is the 'idle' task, which gets called when no other
* tasks can run. It can not be killed, and it cannot sleep. The 'state'
* information in task[0] is never used.
*/
asmlinkage void schedule(void)
{
struct schedule_data * sched_data;
struct task_struct *prev, *next, *p;
struct list_head *tmp;
int this_cpu, c;

spin_lock_prefetch(runqueue_lock);

if (!current->active_mm) BUG();
need_resched_back:
prev = current;
this_cpu = prev->processor;

if (unlikely(in_interrupt())) {
printk("Scheduling in interrupt");
BUG();
}

release_kernel_lock(prev, this_cpu);

/*
* 'sched_data' is protected by the fact that we can run
* only one process per CPU.
*/
sched_data = aligned_data[this_cpu].schedule_data;

spin_lock_irq(runqueue_lock);

/* move an exhausted RR process to be last.. */
if (unlikely(prev->policy == SCHED_RR))
/*
* 如果采用輪轉(zhuǎn)法調(diào)度,則重新檢查counter是否為0, 若是則將其掛到運行隊列的最后
*/
if (!prev->counter) {
prev->counter = NICE_TO_TICKS(prev->nice);
move_last_runqueue(prev);
}

switch (prev->state) {
case TASK_INTERRUPTIBLE:
/*
* 如果是TASK_INTERRUPTIBLE,并且能夠喚醒它的信號已經(jīng)來臨,
* 則將狀態(tài)置為TASK_RUNNING
*/
if (signal_pending(prev)) {
prev->state = TASK_RUNNING;
break;
}
default:
del_from_runqueue(prev);
case TASK_RUNNING:;
}
prev->need_resched = 0;

/*
* this is the scheduler proper:
*/

repeat_schedule:
/*
* Default process to select..
*/
next = idle_task(this_cpu);
c = -1000;
list_for_each(tmp, runqueue_head) {
/*
* 遍歷運行隊列,查找優(yōu)先級最高的進程, 優(yōu)先級最高的進程將獲得CPU
*/
p = list_entry(tmp, struct task_struct, run_list);
if (can_schedule(p, this_cpu)) {
/*
* goodness()中,如果是實時進程,則weight = 1000 p->rt_priority,
* 使實時進程的優(yōu)先級永遠比非實時進程高
*/
int weight = goodness(p, this_cpu, prev->active_mm);
if (weight > c) /注意這里是”>”而不是”>=”,如果權(quán)值相同,則先來的先上
c = weight, next = p;
}
}

/* Do we need to re-calculate counters? */
if (unlikely(!c)) {
/*
* 如果當(dāng)前優(yōu)先級為0,那么整個運行隊列中的進程將重新計算優(yōu)先權(quán)
*/
struct task_struct *p;

spin_unlock_irq(runqueue_lock);
read_lock(tasklist_lock);
for_each_task(p)
p->counter = (p->counter >> 1) NICE_TO_TICKS(p->nice);
read_unlock(tasklist_lock);
spin_lock_irq(runqueue_lock);
goto repeat_schedule;
}

/*
* from this point on nothing can prevent us from
* switching to the next task, save this fact in sched_data.
*/
sched_data->curr = next;
task_set_cpu(next, this_cpu);
spin_unlock_irq(runqueue_lock);

if (unlikely(prev == next)) {
/* We won't go through the normal tail, so do this by hand */
prev->policy = ~SCHED_YIELD;
goto same_process;
}

kstat.context_swtch ;
/*
* there are 3 processes which are affected by a context switch:
*
* prev == .... ==> (last => next)
*
* It's the 'much more previous' 'prev' that is on next's stack,
* but prev is set to (the just run) 'last' process by switch_to().
* This might sound slightly confusing but makes tons of sense.
*/
prepare_to_switch(); {
struct mm_struct *mm = next->mm;
struct mm_struct *oldmm = prev->active_mm;
if (!mm) { /如果是內(nèi)核線程的切換,則不做頁表處理
if (next->active_mm) BUG();
next->active_mm = oldmm;
atomic_inc(oldmm->mm_count);
enter_lazy_tlb(oldmm, next, this_cpu);
} else {
if (next->active_mm != mm) BUG();
switch_mm(oldmm, mm, next, this_cpu); /如果是用戶進程,切換頁表
}

if (!prev->mm) {
prev->active_mm = NULL;
mmdrop(oldmm);
}
}

/*
* This just switches the register state and the stack.
*/
switch_to(prev, next, prev);
__schedule_tail(prev);

same_process:
reacquire_kernel_lock(current);
if (current->need_resched)
goto need_resched_back;
return;
}

----------------------------------------------
ARM Linux 進程調(diào)度(3)

switch_mm中是進行頁表的切換,即將下一個的pgd的開始物理地址放入CP15中的C2
寄存器。進程的pgd的虛擬地址存放在task_struct結(jié)構(gòu)中的pgd指針中,通過
__virt_to_phys宏可以轉(zhuǎn)變成成物理地址。


static inline void
switch_mm(struct mm_struct *prev, struct mm_struct *next,
struct task_struct *tsk, unsigned int cpu)
{
if (prev != next)
cpu_switch_mm(next->pgd, tsk);
}

#define cpu_switch_mm(pgd,tsk) cpu_set_pgd(__virt_to_phys((unsigned long)(pgd)
))

#define cpu_get_pgd()
({
unsigned long pg;
__asm__("mrc p15, 0, %0, c2, c0, 0"
: "=r" (pg));
pg = ~0x3fff;
(pgd_t *)phys_to_virt(pg);
})


switch_to()完成進程上下文的切換,通過調(diào)用匯編函數(shù)__switch_to
完成,其實現(xiàn)比較簡單,也就是保存prev進程的上下文信息,該上下文信息由
context_save_struct結(jié)構(gòu)描述,包括主要的寄存器,然后將next
的上下文信息讀出,信息保存在task_struct中的thread.save中TSS_SAVE標識了thread.
save在task_struct中的位置。


/*
* Register switch for ARMv3 and ARMv4 processors
* r0 = previous, r1 = next, return previous.
* previous and next are guaranteed not to be the same.
*/
ENTRY(__switch_to)
stmfd sp!, {r4 - sl, fp, lr} Store most regs on
stack
mrs ip, cpsr
str ip, [sp, #-4]! Save cpsr_SVC
str sp, [r0, #TSS_SAVE] Save sp_SVC
ldr sp, [r1, #TSS_SAVE] Get saved sp_SVC
ldr r2, [r1, #TSS_DOMAIN]
*
* Returns amount of memory which needs to be reserved.
*/


long ed_init(long mem_start, int mem_end)
{
int i,
ep;

short tshort,
version,
length,
s_ofs;

if (register_blkdev(EPROM_MAJOR,"ed",ed_fops)) {
printk("EPROMDISK: Unable to get major %d.n", EPROM_MAJOR);
return 0;
}
blk_dev[EPROM_MAJOR].request_fn = DEVICE_REQUEST;

for(i=0;i 4) {
printk("EPROMDISK: Length (%d) Too short.n", length);
return 0;
}

ed_length = length * 512;
sector_map = ep 6;
sector_offset = ep s_ofs;

printk("EPROMDISK: Version %d installed, %d bytesn", (int)version, ed_length);
return 0;
}


int get_edisk(unsigned char *buf, int sect, int num_sect)
{
short ss, /* Sector start */
tshort;
int s; /* Sector offset */

for(s=0;s0;) {
sock = bp / EPROM_SIZE;
page = (bp % EPROM_SIZE) / EPAGE_SIZE;
offset = bp % EPAGE_SIZE;

nb = (len offset)>EPAGE_SIZE?EPAGE_SIZE-(offset%EPAGE_SIZE):len;

cr1 = socket[sock] | ((page 4) 0x30) | 0x40; /* no board select for now */
cr2 = (page >> 2) 0x03;
outb((char)cr1,CONTROL_REG1);
outb((char)cr2,CONTROL_REG2);

memcpy(buf bofs,(char *)(EPROM_WINDOW offset),nb);

len -= nb;
bp = nb;
bofs = nb;
}
return 0;
}

med.c代碼如下:
/* med.c - make eprom disk image from ramdisk image */

#include
#include
#include
#define DISK_SIZE (6291456)
#define NUM_SECT (DISK_SIZE/512)

void write_eprom_image(FILE *fi, FILE *fo);

int main(int ac, char **av)
{
FILE *fi,
*fo;

char fin[44],
fon[44];

if (ac > 1) {
strcpy(fin,av[1]);
} else {
strcpy(fin,"hda3.ram");
}

if (ac > 2) {
strcpy(fon,av[2]);
} else {
strcpy(fon,"hda3.eprom");
}

fi = fopen(fin,"r");
fo = fopen(fon,"w");

if (fi == 0 || fo == 0) {
printf("Can't open filesn");
exit(0);
}

write_eprom_image(fi,fo);

fclose(fi);
fclose(fo);
}

void write_eprom_image(FILE *fi, FILE *fo)
{
char *ini;
char *outi; /* In and out images */
short *smap; /* Sector map */
char *sp;
char c = 0;

struct {
unsigned short version;
unsigned short blocks;
unsigned short sect_ofs;
} hdr;

int ns,
s,
i,
fs;

ini = (char *)malloc(DISK_SIZE); /* Max disk size is currently 6M */
outi = (char *)malloc(DISK_SIZE); /* Max disk size is currently 6M */
smap = (short *)malloc(NUM_SECT*sizeof(short));

if (ini == NULL || outi == NULL || smap == NULL) {
printf("Can't allocate memory :(n");
exit(0);
}

if (DISK_SIZE != fread(ini,1,DISK_SIZE,fi)) {
printf("Can't read input file :(n");
exit(0);
}

memcpy(outi,ini,512); /* Copy in first sector */
smap[0] = 0;
ns = 1; /* Number of sectors in outi */





參考書目:
[1]《GNU/Linux編程指南》 (美)K.Wall,M.Watson 清華大學(xué)出版社 1999
[2] 《Linux實用指南》 (美)諾頓、格蕾菲斯著 翟大昆等譯 機械工業(yè)出版社 1999
[3]《系統(tǒng) -- 使用 C 與 C 》 Michael Barr 美商歐萊禮 1999
[4] 《LINUX操作指南》 本社 人民郵電出版社 1999
[5] 《Linux 實用大全》 楊文志編著 北京清華大學(xué)出版社 1999
[6] 《單片機與系統(tǒng)應(yīng)用》 何立民 北京航空航天大學(xué)出版社 1999
[7] 《Linux內(nèi)核源代碼分析》 (美)馬克斯韋爾 機械工業(yè)出版社 2000
[8] 《UNIX操作系統(tǒng)設(shè)計與實現(xiàn)》 陳華瑛、李建國 電子工業(yè)出版社出版 1999

參考文獻:
[1]《frambuffer howto》 Geert Uytterhoeven www.linuxdoc.org 1998
[2] 《RTAI Beginner Guide》Emanuele Bianchi www.rtai.org
[3] 《Booting Linux from EPROM》 Dave Bennett www.linuxjournal.com
[4]《ramdiskhowto》 Paul Gortmaker www.linuxdoc.org 1995
[5]《kernelhowto》 Juan-Mariano de Goyeneche www.linuxdoc.org 2000
[6] 《Embedded Linux Howto》 Sebastien Huet www.linux-embedded.com 2000
[7]《lilohowto》 m.skoric www.linuxdoc.org 2001
[8]《linux from scratch howto》 Gerard Beekmans www.linux-embedded.com 2000
[9]《glibc2howto》 Eric Green www.linux.com 1998
[10] 《Kernel Jorn》Alessandro Rubini Georg Zezchwitz 《Linux Journal》1996
[11]《rtlinux doc》 Michael Barabanov www.rtlinux.com 2001
[12]《the linux boot disk howto》 Tom Fawcett www.linux-embedded.com 2000

linux操作系統(tǒng)文章專題:linux操作系統(tǒng)詳解(linux不再難懂)


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